All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
781
In an arithmetic progression with first term 8 and common difference 3, find the sum of the first 15 terms.
Answer:
435
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*8 + (15-1)*3]. 3. S_n = 435.
782
In an arithmetic progression with first term 5 and common difference 7, find the sum of the first 14 terms.
Answer:
707
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*5 + (14-1)*7]. 3. S_n = 707.
783
In an arithmetic progression with first term 7 and common difference 6, find the sum of the first 17 terms.
Answer:
935
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*7 + (17-1)*6]. 3. S_n = 935.
784
In an arithmetic progression with first term 7 and common difference 3, find the sum of the first 17 terms.
Answer:
527
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*7 + (17-1)*3]. 3. S_n = 527.
785
In an arithmetic progression with first term 5 and common difference 5, find the sum of the first 13 terms.
Answer:
455
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*5 + (13-1)*5]. 3. S_n = 455.
786
In an arithmetic progression with first term 9 and common difference 6, find the sum of the first 13 terms.
Answer:
585
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*9 + (13-1)*6]. 3. S_n = 585.
787
In an arithmetic progression with first term 5 and common difference 4, find the sum of the first 17 terms.
Answer:
629
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*5 + (17-1)*4]. 3. S_n = 629.
788
In an arithmetic progression with first term 9 and common difference 3, find the sum of the first 14 terms.
Answer:
399
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*9 + (14-1)*3]. 3. S_n = 399.
789
In an arithmetic progression with first term 5 and common difference 5, find the sum of the first 16 terms.
Answer:
680
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*5 + (16-1)*5]. 3. S_n = 680.
790
In an arithmetic progression with first term 10 and common difference 7, find the sum of the first 16 terms.
Answer:
1000
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*10 + (16-1)*7]. 3. S_n = 1000.