All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
771
In an arithmetic progression with first term 10 and common difference 4, find the sum of the first 19 terms.
Answer:
874
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*10 + (19-1)*4]. 3. S_n = 874.
772
In an arithmetic progression with first term 11 and common difference 6, find the sum of the first 15 terms.
Answer:
795
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*11 + (15-1)*6]. 3. S_n = 795.
773
In an arithmetic progression with first term 5 and common difference 6, find the sum of the first 15 terms.
Answer:
705
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*5 + (15-1)*6]. 3. S_n = 705.
774
In an arithmetic progression with first term 10 and common difference 3, find the sum of the first 12 terms.
Answer:
318
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*10 + (12-1)*3]. 3. S_n = 318.
775
In an arithmetic progression with first term 7 and common difference 5, find the sum of the first 18 terms.
Answer:
891
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*7 + (18-1)*5]. 3. S_n = 891.
776
In an arithmetic progression with first term 10 and common difference 6, find the sum of the first 12 terms.
Answer:
516
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*10 + (12-1)*6]. 3. S_n = 516.
777
In an arithmetic progression with first term 9 and common difference 7, find the sum of the first 15 terms.
Answer:
870
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*9 + (15-1)*7]. 3. S_n = 870.
778
In an arithmetic progression with first term 11 and common difference 4, find the sum of the first 17 terms.
Answer:
731
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*11 + (17-1)*4]. 3. S_n = 731.
779
In an arithmetic progression with first term 11 and common difference 7, find the sum of the first 14 terms.
Answer:
791
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*11 + (14-1)*7]. 3. S_n = 791.
780
In an arithmetic progression with first term 8 and common difference 7, find the sum of the first 14 terms.
Answer:
749
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*8 + (14-1)*7]. 3. S_n = 749.