All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
761
In an arithmetic progression with first term 7 and common difference 7, find the sum of the first 13 terms.
Answer:
637
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*7 + (13-1)*7]. 3. S_n = 637.
762
In an arithmetic progression with first term 6 and common difference 4, find the sum of the first 18 terms.
Answer:
720
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*6 + (18-1)*4]. 3. S_n = 720.
763
In an arithmetic progression with first term 10 and common difference 6, find the sum of the first 14 terms.
Answer:
686
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*10 + (14-1)*6]. 3. S_n = 686.
764
In an arithmetic progression with first term 5 and common difference 7, find the sum of the first 16 terms.
Answer:
920
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*5 + (16-1)*7]. 3. S_n = 920.
765
In an arithmetic progression with first term 8 and common difference 6, find the sum of the first 15 terms.
Answer:
750
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*8 + (15-1)*6]. 3. S_n = 750.
766
In an arithmetic progression with first term 7 and common difference 7, find the sum of the first 18 terms.
Answer:
1197
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*7 + (18-1)*7]. 3. S_n = 1197.
767
In an arithmetic progression with first term 5 and common difference 4, find the sum of the first 14 terms.
Answer:
434
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*5 + (14-1)*4]. 3. S_n = 434.
768
In an arithmetic progression with first term 7 and common difference 5, find the sum of the first 15 terms.
Answer:
630
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*7 + (15-1)*5]. 3. S_n = 630.
769
In an arithmetic progression with first term 8 and common difference 3, find the sum of the first 18 terms.
Answer:
603
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*8 + (18-1)*3]. 3. S_n = 603.
770
In an arithmetic progression with first term 7 and common difference 3, find the sum of the first 12 terms.
Answer:
282
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*7 + (12-1)*3]. 3. S_n = 282.