All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
801
In an arithmetic progression with first term 5 and common difference 3, find the sum of the first 15 terms.
Answer:
390
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*5 + (15-1)*3]. 3. S_n = 390.
802
In an arithmetic progression with first term 9 and common difference 3, find the sum of the first 16 terms.
Answer:
504
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*9 + (16-1)*3]. 3. S_n = 504.
803
In an arithmetic progression with first term 6 and common difference 7, find the sum of the first 17 terms.
Answer:
1054
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*6 + (17-1)*7]. 3. S_n = 1054.
804
In an arithmetic progression with first term 9 and common difference 6, find the sum of the first 16 terms.
Answer:
864
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*9 + (16-1)*6]. 3. S_n = 864.
805
In an arithmetic progression with first term 11 and common difference 5, find the sum of the first 19 terms.
Answer:
1064
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*11 + (19-1)*5]. 3. S_n = 1064.
806
In an arithmetic progression with first term 8 and common difference 6, find the sum of the first 12 terms.
Answer:
492
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*8 + (12-1)*6]. 3. S_n = 492.
807
In an arithmetic progression with first term 8 and common difference 5, find the sum of the first 16 terms.
Answer:
728
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*8 + (16-1)*5]. 3. S_n = 728.
808
In an arithmetic progression with first term 5 and common difference 6, find the sum of the first 17 terms.
Answer:
901
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*5 + (17-1)*6]. 3. S_n = 901.
809
In an arithmetic progression with first term 5 and common difference 3, find the sum of the first 12 terms.
Answer:
258
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*5 + (12-1)*3]. 3. S_n = 258.
810
In an arithmetic progression with first term 7 and common difference 4, find the sum of the first 13 terms.
Answer:
403
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*7 + (13-1)*4]. 3. S_n = 403.