All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
811
In an arithmetic progression with first term 6 and common difference 7, find the sum of the first 15 terms.
Answer:
825
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*6 + (15-1)*7]. 3. S_n = 825.
812
In an arithmetic progression with first term 11 and common difference 4, find the sum of the first 12 terms.
Answer:
396
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*11 + (12-1)*4]. 3. S_n = 396.
813
In an arithmetic progression with first term 6 and common difference 3, find the sum of the first 16 terms.
Answer:
456
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*6 + (16-1)*3]. 3. S_n = 456.
814
In an arithmetic progression with first term 6 and common difference 7, find the sum of the first 12 terms.
Answer:
534
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*6 + (12-1)*7]. 3. S_n = 534.
815
In an arithmetic progression with first term 6 and common difference 5, find the sum of the first 17 terms.
Answer:
782
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*6 + (17-1)*5]. 3. S_n = 782.
816
In an arithmetic progression with first term 6 and common difference 5, find the sum of the first 14 terms.
Answer:
539
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*6 + (14-1)*5]. 3. S_n = 539.
817
In an arithmetic progression with first term 6 and common difference 4, find the sum of the first 15 terms.
Answer:
510
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*6 + (15-1)*4]. 3. S_n = 510.
818
In an arithmetic progression with first term 11 and common difference 3, find the sum of the first 16 terms.
Answer:
536
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*11 + (16-1)*3]. 3. S_n = 536.
819
In an arithmetic progression with first term 11 and common difference 3, find the sum of the first 13 terms.
Answer:
377
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*11 + (13-1)*3]. 3. S_n = 377.
820
In an arithmetic progression with first term 6 and common difference 3, find the sum of the first 19 terms.
Answer:
627
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*6 + (19-1)*3]. 3. S_n = 627.