All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
751
In an arithmetic progression with first term 5 and common difference 3, find the sum of the first 18 terms.
Answer:
549
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*5 + (18-1)*3]. 3. S_n = 549.
752
In an arithmetic progression with first term 11 and common difference 6, find the sum of the first 18 terms.
Answer:
1116
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*11 + (18-1)*6]. 3. S_n = 1116.
753
In an arithmetic progression with first term 6 and common difference 4, find the sum of the first 12 terms.
Answer:
336
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*6 + (12-1)*4]. 3. S_n = 336.
754
In an arithmetic progression with first term 11 and common difference 5, find the sum of the first 16 terms.
Answer:
776
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*11 + (16-1)*5]. 3. S_n = 776.
755
In an arithmetic progression with first term 8 and common difference 6, find the sum of the first 18 terms.
Answer:
1062
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*8 + (18-1)*6]. 3. S_n = 1062.
756
In an arithmetic progression with first term 7 and common difference 4, find the sum of the first 16 terms.
Answer:
592
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*7 + (16-1)*4]. 3. S_n = 592.
757
In an arithmetic progression with first term 5 and common difference 4, find the sum of the first 19 terms.
Answer:
779
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*5 + (19-1)*4]. 3. S_n = 779.
758
In an arithmetic progression with first term 7 and common difference 6, find the sum of the first 14 terms.
Answer:
644
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*7 + (14-1)*6]. 3. S_n = 644.
759
In an arithmetic progression with first term 6 and common difference 6, find the sum of the first 18 terms.
Answer:
1026
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*6 + (18-1)*6]. 3. S_n = 1026.
760
In an arithmetic progression with first term 11 and common difference 3, find the sum of the first 18 terms.
Answer:
657
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*11 + (18-1)*3]. 3. S_n = 657.