All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
791
In an arithmetic progression with first term 6 and common difference 3, find the sum of the first 13 terms.
Answer:
312
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*6 + (13-1)*3]. 3. S_n = 312.
792
In an arithmetic progression with first term 8 and common difference 4, find the sum of the first 17 terms.
Answer:
680
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*8 + (17-1)*4]. 3. S_n = 680.
793
In an arithmetic progression with first term 8 and common difference 4, find the sum of the first 12 terms.
Answer:
360
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*8 + (12-1)*4]. 3. S_n = 360.
794
In an arithmetic progression with first term 9 and common difference 3, find the sum of the first 19 terms.
Answer:
684
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*9 + (19-1)*3]. 3. S_n = 684.
795
In an arithmetic progression with first term 9 and common difference 5, find the sum of the first 14 terms.
Answer:
581
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*9 + (14-1)*5]. 3. S_n = 581.
796
In an arithmetic progression with first term 10 and common difference 3, find the sum of the first 17 terms.
Answer:
578
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*10 + (17-1)*3]. 3. S_n = 578.
797
In an arithmetic progression with first term 8 and common difference 4, find the sum of the first 14 terms.
Answer:
476
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*8 + (14-1)*4]. 3. S_n = 476.
798
In an arithmetic progression with first term 10 and common difference 6, find the sum of the first 17 terms.
Answer:
986
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*10 + (17-1)*6]. 3. S_n = 986.
799
In an arithmetic progression with first term 6 and common difference 6, find the sum of the first 13 terms.
Answer:
546
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*6 + (13-1)*6]. 3. S_n = 546.
800
In an arithmetic progression with first term 6 and common difference 5, find the sum of the first 19 terms.
Answer:
969
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*6 + (19-1)*5]. 3. S_n = 969.