All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
731
In an arithmetic progression with first term 11 and common difference 5, find the sum of the first 14 terms.
Answer:
609
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*11 + (14-1)*5]. 3. S_n = 609.
732
In an arithmetic progression with first term 9 and common difference 7, find the sum of the first 12 terms.
Answer:
570
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*9 + (12-1)*7]. 3. S_n = 570.
733
In an arithmetic progression with first term 10 and common difference 4, find the sum of the first 14 terms.
Answer:
504
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*10 + (14-1)*4]. 3. S_n = 504.
734
In an arithmetic progression with first term 8 and common difference 3, find the sum of the first 13 terms.
Answer:
338
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*8 + (13-1)*3]. 3. S_n = 338.
735
In an arithmetic progression with first term 8 and common difference 5, find the sum of the first 13 terms.
Answer:
494
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*8 + (13-1)*5]. 3. S_n = 494.
736
In an arithmetic progression with first term 9 and common difference 6, find the sum of the first 19 terms.
Answer:
1197
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*9 + (19-1)*6]. 3. S_n = 1197.
737
In an arithmetic progression with first term 11 and common difference 7, find the sum of the first 17 terms.
Answer:
1139
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*11 + (17-1)*7]. 3. S_n = 1139.
738
In an arithmetic progression with first term 8 and common difference 5, find the sum of the first 19 terms.
Answer:
1007
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*8 + (19-1)*5]. 3. S_n = 1007.
739
In an arithmetic progression with first term 11 and common difference 6, find the sum of the first 13 terms.
Answer:
611
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*11 + (13-1)*6]. 3. S_n = 611.
740
In an arithmetic progression with first term 10 and common difference 7, find the sum of the first 13 terms.
Answer:
676
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*10 + (13-1)*7]. 3. S_n = 676.