All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
721
In what ratio should ingredients costing ₹24 and ₹36 per kg be mixed to obtain a mixture worth ₹32.0 per kg?
Answer:
4.0 : 8.0
Step-by-step solution: 1. Use the rule of allegation: (price2 - mean) : (mean - price1). 2. Required ratio = (36 - 32.0) : (32.0 - 24). 3. Therefore the ratio is 4.0 : 8.0.
722
In what ratio should ingredients costing ₹23 and ₹37 per kg be mixed to obtain a mixture worth ₹32.0 per kg?
Answer:
5.0 : 9.0
Step-by-step solution: 1. Use the rule of allegation: (price2 - mean) : (mean - price1). 2. Required ratio = (37 - 32.0) : (32.0 - 23). 3. Therefore the ratio is 5.0 : 9.0.
723
In what ratio should ingredients costing ₹20 and ₹39 per kg be mixed to obtain a mixture worth ₹31.5 per kg?
Answer:
7.5 : 11.5
Step-by-step solution: 1. Use the rule of allegation: (price2 - mean) : (mean - price1). 2. Required ratio = (39 - 31.5) : (31.5 - 20). 3. Therefore the ratio is 7.5 : 11.5.
724
In what ratio should ingredients costing ₹18 and ₹38 per kg be mixed to obtain a mixture worth ₹30.0 per kg?
Answer:
8.0 : 12.0
Step-by-step solution: 1. Use the rule of allegation: (price2 - mean) : (mean - price1). 2. Required ratio = (38 - 30.0) : (30.0 - 18). 3. Therefore the ratio is 8.0 : 12.0.
725
In an arithmetic progression with first term 9 and common difference 5, find the sum of the first 17 terms.
Answer:
833
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*9 + (17-1)*5]. 3. S_n = 833.
726
In an arithmetic progression with first term 9 and common difference 4, find the sum of the first 15 terms.
Answer:
555
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*9 + (15-1)*4]. 3. S_n = 555.
727
In an arithmetic progression with first term 5 and common difference 6, find the sum of the first 12 terms.
Answer:
456
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*5 + (12-1)*6]. 3. S_n = 456.
728
In an arithmetic progression with first term 7 and common difference 6, find the sum of the first 19 terms.
Answer:
1159
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*7 + (19-1)*6]. 3. S_n = 1159.
729
In an arithmetic progression with first term 9 and common difference 4, find the sum of the first 13 terms.
Answer:
429
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*9 + (13-1)*4]. 3. S_n = 429.
730
In an arithmetic progression with first term 10 and common difference 5, find the sum of the first 15 terms.
Answer:
675
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*10 + (15-1)*5]. 3. S_n = 675.