Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
1
In an arithmetic progression with first term 9 and common difference 5, find the sum of the first 17 terms.
Answer:
833
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*9 + (17-1)*5]. 3. S_n = 833.
2
In an arithmetic progression with first term 9 and common difference 4, find the sum of the first 15 terms.
Answer:
555
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*9 + (15-1)*4]. 3. S_n = 555.
3
In an arithmetic progression with first term 5 and common difference 6, find the sum of the first 12 terms.
Answer:
456
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*5 + (12-1)*6]. 3. S_n = 456.
4
In an arithmetic progression with first term 7 and common difference 6, find the sum of the first 19 terms.
Answer:
1159
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*7 + (19-1)*6]. 3. S_n = 1159.
5
In an arithmetic progression with first term 9 and common difference 4, find the sum of the first 13 terms.
Answer:
429
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*9 + (13-1)*4]. 3. S_n = 429.
6
In an arithmetic progression with first term 10 and common difference 5, find the sum of the first 15 terms.
Answer:
675
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*10 + (15-1)*5]. 3. S_n = 675.
7
In an arithmetic progression with first term 11 and common difference 5, find the sum of the first 14 terms.
Answer:
609
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*11 + (14-1)*5]. 3. S_n = 609.
8
In an arithmetic progression with first term 9 and common difference 7, find the sum of the first 12 terms.
Answer:
570
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*9 + (12-1)*7]. 3. S_n = 570.
9
In an arithmetic progression with first term 10 and common difference 4, find the sum of the first 14 terms.
Answer:
504
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*10 + (14-1)*4]. 3. S_n = 504.
10
In an arithmetic progression with first term 8 and common difference 3, find the sum of the first 13 terms.
Answer:
338
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*8 + (13-1)*3]. 3. S_n = 338.