All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
4401
A tradesman gives 4% discount on the marked price and gives 1 article free for buying every 15 articles and thus gains 35%. The marked price is above the cost price by:
Answer:
50%
Let CP of 1 article = 100. Total CP of 16 articles (15 sold + 1 free) = 1600. Total SP = 1600 * 1.35 = 2160. But he receives money for only 15 articles, so SP of each of the 15 articles = 2160 / 15 = 144. This SP is after a 4% discount on MP. So, 96% of MP = 144 => MP = 144 / 0.96 = 150. Since MP is 150 and CP is 100, the markup is 50%.
4402
A grocer purchased 80 kg of sugar at Rs. 13.50 per kg and mixed it with 120 kg sugar at Rs. 16 per kg. At what rate should he sell the mixture to gain 16%?
Answer:
Rs. 17.40
Total Cost = (80 * 13.50) + (120 * 16) = 1080 + 1920 = 3000. Total quantity = 200 kg. CP per kg = 3000 / 200 = Rs. 15. For 16% profit, SP = 15 * 1.16 = Rs. 17.40 per kg.
4403
A shopkeeper professes to sell his goods at cost price, but he uses a false weight of 950g for a kg. What is his gain percent?
Answer:
5.26%
Error = 1000 - 950 = 50g. Gain % = (Error / True Value - Error) * 100 = (50 / 950) * 100 = (5 / 95) * 100 = (1 / 19) * 100 ≈ 5.26%.
4404
An article costs Rs. 500. The marked price is set such that after a 10% discount, there is a profit of 20%. Find the marked price.
Answer:
Rs. 666.67
CP = 500. Profit = 20%, so SP = 500 * 1.20 = Rs. 600. A 10% discount on MP gives SP, so 90% of MP = 600. MP = 600 / 0.90 = 6000 / 9 = Rs. 666.67.
4405
If a reduction of 10% in the price of sugar enables a housewife to buy 5 kg more for Rs. 300, find the original price per kg of sugar.
Answer:
Rs. 6.66
10% of 300 = Rs. 30. This Rs. 30 buys 5 kg extra. So, the reduced price = 30 / 5 = Rs. 6 per kg. Since the reduced price is 90% of the original price, Original Price = 6 / 0.90 = 60 / 9 = Rs. 6.66 per kg.
4406
A fruit seller buys 100 kg of apples at Rs. 50 per kg. 10 kg of apples were rotten and thrown away. At what rate per kg should he sell the remaining apples to get a 20% overall profit?
Answer:
Rs. 66.67
Total CP = 100 * 50 = Rs. 5000. Desired total SP for a 20% profit = 5000 * 1.20 = Rs. 6000. Remaining apples = 100 - 10 = 90 kg. Required SP per kg = 6000 / 90 = 600 / 9 = Rs. 66.67.
4407
A man buys apples at 10 for Rs. 25 and sells them at 9 for Rs. 25. Find his profit percentage.
Answer:
11.11%
CP of 1 apple = 25 / 10 = Rs. 2.50. SP of 1 apple = 25 / 9 = Rs. 2.77... Profit = 25/9 - 25/10 = 250/90 - 225/90 = 25/90. Profit % = ((25/90) / (25/10)) * 100 = (10 / 90) * 100 = 11.11%.
4408
A trader mixes 20 kg of wheat at Rs. 15 per kg with 30 kg of wheat at Rs. 13 per kg. At what price per kg should he sell the mixture to gain 33.33%?
Answer:
Rs. 18.40
Total Cost Price = (20 * 15) + (30 * 13) = 300 + 390 = 690. Total weight = 50 kg. CP per kg = 690 / 50 = Rs. 13.80. Gain desired is 33.33%, which is 1/3. SP = CP * (1 + 1/3) = CP * 4/3 = 13.80 * 4/3 = 4.60 * 4 = Rs. 18.40.
4409
By selling an article for Rs. 21, a man lost a percentage equal to the cost price of the article. What was the cost price?
Answer:
Rs. 30 or Rs. 70
Let the CP be x. Loss % = x%. Loss = (x/100) * x = x^2 / 100. We know SP = CP - Loss => 21 = x - (x^2 / 100). Multiply by 100: 2100 = 100x - x^2. x^2 - 100x + 2100 = 0. Solving this quadratic equation: (x - 30)(x - 70) = 0. So, x = 30 or 70. Both values are valid.
4410
If a manufacturer gains 10%, wholesale dealer 15% and retailer 25%, find the cost of production of a table if the retail price is Rs. 1265.
Answer:
Rs. 800
Let the cost of production be x. x * 1.10 * 1.15 * 1.25 = 1265. x * 1.58125 = 1265. x = 1265 / 1.58125 = Rs. 800.