All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
4111
Find the compound interest on Rs. 4000 for 9 months at 6% per annum, interest being payable quarterly.
Answer:
Rs. 182.71
Quarterly rate R = 6/4 = 1.5%. Time n = 9 months = 3 quarters. Amount = 4000(1 + 1.5/100)³ = 4000(1.015)³ = 4000 × 1.045678375 = 4182.7135. Compound Interest = 4182.71 - 4000 = Rs. 182.71.
4112
What is the difference between compound interest and simple interest for 2 years on a sum of Rs. 10000 at 5% per annum?
Answer:
Rs. 25
The formula for the difference between CI and SI for 2 years is D = P(R/100)². D = 10000(5/100)² = 10000(1/400) = Rs. 25.
4113
The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is:
Answer:
Rs. 500
Effective CI rate for 2 years at 10% is 21%. 21% of P = 525, so P = (525 / 21) × 100 = 2500. Double the time = 4 years, half the rate = 5%. SI = (2500 × 5 × 4) / 100 = Rs. 500.
4114
The simple interest on a certain sum of money for 2.5 years at 12% per annum is Rs. 40 less than the simple interest on the same sum for 3.5 years at 10% per annum. Find the sum.
Answer:
Rs. 800
Let the sum be P. SI1 = (P × 12 × 2.5)/100 = 0.30P. SI2 = (P × 10 × 3.5)/100 = 0.35P. Given SI2 - SI1 = 40. So, 0.35P - 0.30P = 40 => 0.05P = 40. P = 40 / 0.05 = Rs. 800.
4115
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer:
Rs. 6400
Let investment in B be x, so A is 13900 - x. Total SI for 1 year = 3508 / 2 = 1754. 14% of (13900 - x) + 11% of x = 1754. 1946 - 0.14x + 0.11x = 1754. 0.03x = 192. x = 192 / 0.03 = 6400. Thus, Rs. 6400 was invested in Scheme B.
4116
If the simple interest on a sum of money is Rs. 256 and the rate of interest is 8% per annum, find the time period if the principal is Rs. 800.
Answer:
4 years
Time T = (SI × 100) / (P × R) = (256 × 100) / (800 × 8) = 25600 / 6400 = 4 years.
4117
A sum of Rs. 12500 amounts to Rs. 15500 in 4 years at the rate of simple interest. What is the rate of interest?
Answer:
6%
SI = 15500 - 12500 = Rs. 3000. Rate = (SI × 100) / (P × T) = (3000 × 100) / (12500 × 4) = 300000 / 50000 = 6%.
4118
The simple interest on Rs. 10 for 4 months at the rate of 3 paise per rupee per month is:
Answer:
Rs. 1.20
The rate is 3 paise per rupee per month, which means 3% per month. Since the time is given in months, we don't need to convert to years. SI = P × R × T = 10 × (3/100) × 4 = 120/100 = Rs. 1.20.
4119
At what rate of simple interest per annum will a sum become 7/4 of itself in 4 years?
Answer:
18.75%
Amount A = (7/4)P. SI = A - P = (7/4)P - P = (3/4)P. Rate R = (SI × 100) / (P × T) = ((3/4)P × 100) / (P × 4) = 75 / 4 = 18.75%.
4120
Rs. 1000 is invested at 5% per annum simple interest. If the interest is added to the principal after every 10 years, the amount will become Rs. 2000 after:
Answer:
16.66 years
SI for first 10 years = (1000 × 5 × 10)/100 = 500. New principal after 10 years = 1000 + 500 = 1500. We need it to reach 2000, so we need 500 more interest. Time to earn 500 on 1500 = (500 × 100) / (1500 × 5) = 50000 / 7500 = 20/3 = 6.66 years. Total time = 10 + 6.66 = 16.66 years.