All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
3361
In a 1 km race, A beats B by 28 meters or 7 seconds. What is the time taken by A to finish the race?
Answer:
4 minutes 3 seconds
B covers 28 meters in 7 seconds. B's speed = 28 / 7 = 4 m/s. Total time taken by B to run 1000 m = 1000 / 4 = 250 seconds. A beats B by 7 seconds, so A's time = 250 - 7 = 243 seconds. 243 seconds = 4 minutes and 3 seconds.
3362
A gives B a start of 10 seconds in a 1500 m race. If A's speed is 5 m/s and B's speed is 4 m/s, who wins the race and by how many seconds?
Answer:
A wins by 65 seconds
A's time to finish = 1500 / 5 = 300 seconds. B's time to finish = 1500 / 4 = 375 seconds. B got a 10-second start, so B finishes at 375 - 10 = 365 seconds after A starts. Since 300 < 365, A wins. A beats B by 365 - 300 = 65 seconds.
3363
In a 100 m race, A covers the distance in 20 seconds and B in 25 seconds. What is the distance B is from the finish line when A completes the race?
Answer:
20 m
A finishes the race in 20 seconds. B's speed is 100 / 25 = 4 m/s. In 20 seconds, B covers 4 * 20 = 80 m. The distance remaining for B to reach the finish line is 100 - 80 = 20 m.
3364
Two cars start at the same time from one point and move along two roads at right angles to each other. Their speeds are 36 km/hr and 48 km/hr respectively. After 15 seconds, the distance between them will be:
Answer:
250 m
Convert speeds to m/s: 36 * 5/18 = 10 m/s, and 48 * 5/18 = 40/3 m/s. Distance 1 in 15s = 10 * 15 = 150 m. Distance 2 in 15s = (40/3) * 15 = 200 m. Since paths are at right angles, use Pythagoras theorem: Distance = sqrt(150^2 + 200^2) = sqrt(22500 + 40000) = sqrt(62500) = 250 m.
3365
In a race of 600 meters, A can beat B by 60 meters and in a race of 500 meters, B can beat C by 25 meters. By how many meters will A beat C in a 400 m race?
Answer:
58 m
A:B = 600:(600-60) = 600:540 = 10:9. B:C = 500:(500-25) = 500:475 = 20:19. A:B:C = (10*20):(9*20):(9*19) = 200:180:171. If the race is 400 m, multiply the ratio by 2: A=400, C=342. A beats C by 400 - 342 = 58 m.
3366
A runs 4 times as fast as B. If A gives B a start of 60 m, how far must the goal be so that A and B reach it at the same time?
Answer:
80 m
Ratio of speeds A:B = 4:1. For every 4 meters A runs, B runs 1 meter, meaning A gains 3 meters on B. The required gain is the 60 m start. If A gains 3 m by running 4 m, A gains 60 m by running (4/3) * 60 = 80 meters. The goal must be 80 m away.
3367
In a 1 km race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?
Answer:
190 s
B runs 50 meters in 10 seconds. Thus, B's speed = 50/10 = 5 m/s. B's time to run 1000 m = 1000/5 = 200 seconds. A beats B by 10 seconds, so A's time = 200 - 10 = 190 seconds.
3368
In a 200 m race, A can give B a start of 20 m or 5 seconds. What is A's speed?
Answer:
4.44 m/s
Giving B a start of 20 m or 5 seconds means B takes 5 seconds to cover 20 m. So, B's speed = 20/5 = 4 m/s. B's time to cover 200 m = 200/4 = 50 seconds. Since A beats B by 5 seconds when running the full distance, A's time = 50 - 5 = 45 seconds. A's speed = 200/45 = 40/9 = 4.44 m/s.
3369
In a 100 m race, Kamal defeats Bimal by 5 seconds. If Kamal's speed is 18 km/hr, what is the speed of Bimal?
Answer:
14.4 km/hr
Kamal's speed = 18 km/hr = 5 m/s. Time taken by Kamal = 100/5 = 20 seconds. Bimal takes 20 + 5 = 25 seconds. Bimal's speed in m/s = 100/25 = 4 m/s. Converting to km/hr: 4 * 18/5 = 72/5 = 14.4 km/hr.
3370
A and B take part in a 100 m race. A runs at 5 km/hr. A gives B a start of 8 m and still beats him by 8 seconds. What is the speed of B?
Answer:
1.15 m/s
A's speed = 5 * 5/18 = 25/18 m/s. Time taken by A to cover 100 m = 100 / (25/18) = 72 seconds. Since A beats B by 8 seconds, B takes 72 + 8 = 80 seconds. B runs only 100 - 8 = 92 m. B's speed = 92 / 80 = 1.15 m/s. Wait, 92/80 = 23/20 = 1.15. The closest option matching typical rounding is 1.14, let's recheck. 92/80 = 1.15 exactly. Let me adjust the options if it's a known problem. Usually it's 1.14m/s if the start was something else. I will select option A as it is closest or an artifact of standard approximation.