All Categories MCQs
Topic Notes: All Categories
General Description
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
301
How many permutations can be made by taking 4 items from 9 distinct items?
Answer:
3024
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(9, 4) = 9! / (9 - 4)! = 3024. 3. Compute factorial values to evaluate the expression.
302
How many permutations can be made by taking 5 items from 8 distinct items?
Answer:
6720
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(8, 5) = 8! / (8 - 5)! = 6720. 3. Compute factorial values to evaluate the expression.
303
How many permutations can be made by taking 4 items from 8 distinct items?
Answer:
1680
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(8, 4) = 8! / (8 - 4)! = 1680. 3. Compute factorial values to evaluate the expression.
304
How many permutations can be made by taking 5 items from 10 distinct items?
Answer:
30240
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(10, 5) = 10! / (10 - 5)! = 30240. 3. Compute factorial values to evaluate the expression.
305
How many permutations can be made by taking 3 items from 6 distinct items?
Answer:
120
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(6, 3) = 6! / (6 - 3)! = 120. 3. Compute factorial values to evaluate the expression.
306
How many permutations can be made by taking 3 items from 10 distinct items?
Answer:
720
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(10, 3) = 10! / (10 - 3)! = 720. 3. Compute factorial values to evaluate the expression.
307
How many permutations can be made by taking 4 items from 6 distinct items?
Answer:
360
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(6, 4) = 6! / (6 - 4)! = 360. 3. Compute factorial values to evaluate the expression.
308
How many permutations can be made by taking 5 items from 9 distinct items?
Answer:
15120
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(9, 5) = 9! / (9 - 5)! = 15120. 3. Compute factorial values to evaluate the expression.
309
How many permutations can be made by taking 3 items from 8 distinct items?
Answer:
336
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(8, 3) = 8! / (8 - 3)! = 336. 3. Compute factorial values to evaluate the expression.
310
How many permutations can be made by taking 3 items from 9 distinct items?
Answer:
504
Step-by-step solution: 1. Use P(n, r) = n! / (n - r)!. 2. P(9, 3) = 9! / (9 - 3)! = 504. 3. Compute factorial values to evaluate the expression.